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δ= √2+1
φ= (√5+1)/2
π= arctan1+arctan2+arctan3
τ= 2×(arctan1+arctan2+arctan3)
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δ= √2+1
φ= (√5+1)/2
π= arctan1+arctan2+arctan3
τ= 2×(arctan1+arctan2+arctan3)