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Banbanoso xd @UCSaIsbUEaG_xwNQIy9goNqw@youtube.com

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Hola, gente!! En este canal podrán encontrar edits, versus,


Welcoem to posts!!

in the future - u will be able to do some more stuff here,,,!! like pat catgirl- i mean um yeah... for now u can only see others's posts :c

Banbanoso xd
Posted 10 hours ago

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Banbanoso xd
Posted 11 hours ago

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Banbanoso xd
Posted 1 day ago

SIX SEVEN🗣🔥

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Banbanoso xd
Posted 1 day ago

Ya está listo, gente :)
Solo hay que esperar los 400 subs

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Banbanoso xd
Posted 1 day ago

‪@foxgaming2023‬

The depth is now 10 cm

0.1*2.8*4.34=1.2152 m^3

The gate should be made of reinforced steel because of the danger in that area

So, reinforced steel >>> average steel

Average steel has a maximum resistance of 700 MPa

P = 700 MPa

e = 20% in the case of steel

U = 0.5*700,000,000*0.2=70,000,000 J/m^3

1.2152*70,000,000=85,064,000 Joules (Small Building Level)

85064000/3=28,354,666.6667 Joules (Small Building Level)

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Banbanoso xd
Posted 1 day ago

‪@foxgaming2023‬ Here's the calc

The measures don't change, but the resulting energy yes

U = 0-5*P*e

P = 250 MPa (in the case of steel)

e = 20% (in the case of steel)

0.5*250,000,000*0.2=25,000,000 J/m^3

Now let's find the volume

4.34*0.2*2.8=2.4304 m^3

2.4304*25,000,000=60,760,000 Joules (Small Building Level)

60760000/3=20,253,333.3333 Joules (Wall Level+)

Well, I had told you that it was only 19 MJ but i recalced it xd

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Banbanoso xd
Posted 2 days ago

Recalculemos al Ciervo doblando barrotes de metal

El Ciervo: 357 cm

Cabeza del Ciervo: 127 cm

Longitud de los barrotes: 210 cm

Espesor: 25.4 cm

U = 25,000,000 J/m^3 (en el caso del acero)

R = 12.7 cm

V = pi*0.127^2*2.1=0.10640857061 m^3

0.10640857061*25,000,000=2,660,214.26526 Joules (Nivel Muro)

Como son 5 barrotes, se multiplica por 5

2660214.26526 *5=13,301,071.3263 Joules (Nivel Muro+)

Ahora vamos con la fuerza

e = 20% en el caso del acero

D = 0.2*2.1=0.42

F = E / D

E = 2,660,214.26526

F = 2,660,214.26526/0.42=6,333,843.48871 N

6333843.48871/9800=646.310560073 toneladas (Clase K)

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Banbanoso xd
Posted 2 days ago

Calculemos a CatNap cortando placas de metal

GrabPack: 28.6 cm | 122 px

28.6/122=0.2344262295 cm

Longitud de las marcas: 400 px (máximo)

0.2344262295*400=93.7704918033 cm

Espesor de las marcas: 80 px

0.2344262295*80=18.7540983607 cm

Espesor de la placa: 4.4 cm

Á = (0.04*0.187540983607)/2=0.00375081967 m^2

V = 0.00375081967*0.937704918033=0.00351716205 m^3

U = 0.5*P*e

P = 250 MPa

e = 20% en el caso del acero

U = 0.5*250,000,000*0.2 = 25,000,000 J/m^3

E = 25,000,000*0.00351716205=87,929.0512803 Joules (Nivel Muro)

Ahora vamos con la fuerza

D = 0.2*0.937704918033=0.1875409836 m

F = E / D

E = 87,929.0512803 J

F = 87,929.0512803/0.1875409836=468,852.458766 N

468852.458766/9800=47.8420876292 toneladas (Clase 50)

‪@Scalix_VSDebates‬ ¿qué opinas?

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Banbanoso xd
Posted 3 days ago

Veamos la velocidad de Nabnaleena

Vamos a ver la distancia que Nabnaleena puede recorrer en un frame a 60 fps

Jumbo Josh (GOBB 7): 520 cm

Distancia: 247.611 cm

Tiempo: 1 frame

2.47611/(1/60)=148.5666 m/s o 534.83976 km/h (Subsónico)

Nabnab debería escalar de Nabnaleena

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Banbanoso xd
Posted 3 days ago

¿¿¿TAN PRONTO 350 SUBS???
Muchas gracias :D
Ni siquiera me dieron tiempo de hacer un especial :'(
Bueno, no importa
Lo haré para el especial 400 (si es que me dan tiempo :v)

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