Channel Avatar

AK MtCourse @UCD-nun4equVuuPs9L4WxkMw@youtube.com

None subscribers - no pronouns set

पढ़ाई पर अब नही होगा Force, क्योंकि हम लेकर आ रहे हैं "AK MtC


08:54
The Angles Of Elevation Of The Top Of A Tower From Two Points At A Distance Of 4 M And 9 M From The
14:56
A Straight Highway Leads To The Foot Of A Tower A Man Standing At The Top Of The Tower Observes A
19:10
A 1.2 M Tall Girl Spots A Balloon Moving With The Wind In A Horizontal Line At A Height Of 88.2 M
14:31
As Observed From The Top Of A 75m High Lighthouse From The Sea Level The Angles Of Depression Of Two
15:30
From The Top Of A 7m High Building The Angle Of Elevation Of The Top Of A Tower Is 60 Degree
13:39
A TV Tower Stands Vertically On A Bank Of A Canal From A Point On The Other Bank Directly Opposite
15:03
Two Poles Of Equal Heights Are Standing Opposite Each Other On Either Side Of The Road Which Is 80 M
09:31
The Angle Of Elevation Of The Top Of A Building From The Foot Of The Tower Is 30° And The Angle Of
12:23
A Statue 1.6 M Tall Stands On The Top Of A Pedestal From A Point On The Ground The Angle Of
06:56
From A Point On The Ground The Angles Of Elevation Of The Bottom And The Top Of A Transmission Tower
25:28
1.5 M Tall Boy Is Standing At Some Distance From A 30m Tall Building The Angle Of Elevation From His
07:36
A Kite Is Flying At A Height Of 60m Above The Ground The String Attached To The Kite Is Temporarily
08:02
The Angle Of Elevation Of The Top Of A Tower From A Point On The Ground Which Is 30 m Away From The
15:11
A Contractor Plans To Install Two Slides For The Children To Play In A Park For The Children Below
23:35
A Tree Breaks Due To Storm And The Broken Part Bends So That The Top Of The Tree Touches The Ground
09:28
A Circus Artist Is Climbing A 20m Long Rope Which Is Tightly Stretched And Tied From The Top
22:02
Some Applications Of Trigonometry Class 10 Introduction | Some Applications Of Trigonometry
07:40
1+Tan2A/1+Cot2A=(1-tanA/1-cotA)2=Tan2A | Prove That 1+Tan2A/1+Cot2A=(1-tanA/1-cotA)2=Tan2A
07:11
(Cosec A-sin A)(Sec A-cos A)=(1)/(Tan A+Cot A) | (Cosec A - Sin A) (Sec A - Cos A) =1/(TanA + CotA)
06:30
(SinA+CosecA)2+(CosA+SecA 2=7+Tan2A+Cot2A | (SinA+CosecA)2+(CosA+SecA)2=7+Tan2A+Cot2A
05:37
Sin Theta Minus 2 Sin Cube Theta By 2 Cos Cube Theta Minus Cos Theta Is Equal To Tan Theta
06:53
Under Root 1 + Sin A Upon 1 Minus Sin A Is Equal To Sec A + Tan A | Root 1+SinA/1-sinA=SecA+TanA
13:35
CosA-SinA+1/CosA+SinA-1=CosecA+CotA | Cos A - Sin A + 1/Cos A + Sin A - 1 = Cosec A + Cot A
08:26
1+Sec A/Sec A=Sin2A/1-CosA | 1 + Sec A Upon Sec A Is Equal To Sin Square A Upon 1 Minus Cos A
20:25
Tan Theta/1-cot Theta + Cot Theta/1-tan Theta= 1+ Sec Theta Cosec Theta | Tanθ 1−cotθ+ Cotθ 1−tanθ
06:48
CosA/1+SinA+1+SinA/CosA=2 Sec A | Cos A Upon 1 + Sin A + 1 + Sin A Upon Cos A Is Equal To 2 Second
09:11
(Cosec-Cot)2=1-Cos/1+Cos | Show That (Cosec Theta-Cot Theta)^(2)=(1-Cos Theta)/(1+Cos Theta)
14:45
Choose The Correct Option And Justify Your Choice | 9 Sec2a - 9 Tan2a Is Equal To
08:11
Evaluate Sin 2 63+Sin227/Cos217+Cos273 | Evaluate Sin 25 Cos 65 + Cos 25 Sin 65
08:52
Write All The Other Trigonometric Ratios Of Angle A In Terms Of Sec A
09:51
Express The Trigonometric Ratios Sin A Seca And Tana In Terms Of Cot A
03:37
Express Sin 67° + Cos 75° In Terms Of Trigonometric Ratios Of Angles Between 0° And 45°
04:39
If A B And C Are Interior Angles Of Triangle ABC Then Show That Sin (B+C/2) Is Equal To Cos A/2
04:55
If Sec 4A=Cosec(A-20) Where 4A Is An Acute Angle Find The Value Of A
02:46
If Tan A=Cot B Prove That A+B=90 | If Tan A=Cot B Prove That A+B=90°
04:16
If Tan 2A Is Equal To Cot A Minus 18 Degrees Where To A Is An Acute Angle Find The Value Of A
12:25
Show That Tan 48°tan23°tan42°tan67°=1| Show That Cos 38°cos 52°-sin38°sin 52°=0
10:15
Evaluate Sin18/Cos72 | Evaluate Tan26/Cot64 | Evaluate Cos 48 - Sin 42 | Evaluate Cosec 31°-sec 59°
14:16
State Whether The Following Statements Are True Or False Justify Your Answer
08:03
If Tan A + B Is Equal To Root 3 And 10 A Minus B Is Equal To 1 By Root 3
10:22
Choose The Correct Option And Justify Your Choice | Choose The Correct Option Class 10th
25:40
Evaluate The Following Sin 60 Cos 30 + Sin 30 Cos 60 | Evaluate The Following Cos45/Sec30+Cosec30
13:52
State Whether The Following Statements Are True Or False Justify Your Answer
08:14
In Triangle PQR Right Angled At Q PR + QR Is Equal To 25cm And PQ Is Equal To 5cm Determine The
08:07
In Triangle Abc Right Angled At B If Tan A Is Equal To 1/√3 Find The Value Of
07:48
If 3 Cot A=4 Show That (1-tan^(2)A)/(1+tan^(2)A)=Cos^(2a-sin^(2)A Or Not
10:30
If Cot=7/8 Evaluate (1+sina)(1-sina)/(1+cosa)(1-cosa) | If Cot Theta Is Equal To 7 By 8 Then Find
08:28
If Angle A And Angle B Are Acute Angles Such That Cosa Is Equal To Cos B Then Show That Angle A Is
08:19
Given Sec Theta Is Equal To 13 By 12 Calculate All Other Trigonometric Ratios
08:46
Given 15 Cot A Is Equal To 8 Find Sin A And Sec A | Given 15 Cota=8 Find Sin A Sec A
08:24
If Sin A=(3)/(4) Then Find Value Of Cos A | If Sin A=(3)/(4) Then Find Value Of Cos A And Tan A
07:31
In Fig 8.13 Find Tan P-cot R | In Figure 8.13 Find Tan P - Cot R | In Figure 8.13 Find P - Cot R
13:03
In Triangle ABC Right Angled At B AB=24 cm BC=7 cm Determine (i) Sin A, Cos A (ii) Sin C, Cos C
23:10
Class 10 Maths Chapter 8 Trigonometry Introduction | Trigonometry Class 10 Introduction
16:05
You Have Studied In Class 9 That A Median Of A Triangle Divides It Into Two Triangles Of Equal Areas
15:50
Find The Area Of Quadrilateral Whose Vertices Taken In Order Are (-4 -2) (-3 -5) (3 -2) & (2 3)
12:59
Find The Area Of The Triangle Formed By Joining The Midpoints Of The Sides Of The Triangle
10:52
In Each Of The Following Find The Value Of K For Which The Points Are Collinear (7 -2) (5 1) (3 k)
10:25
Find The Area Of The Triangle Whose Vertices Are 2 3 - 1 0 2 - 4 | (-5 -1) (3 -5) (5 2)
07:34
Find The Area Of A Rhombus If Its Vertices Are (3 0) (4 5) (-1 4) And (-2 -1) Taken In Order