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Me Asthmatic_M@thematics. @UC48d9QL_P2ec2YQBt70nxFw@youtube.com

5.4K subscribers

Hey guys, Welcome to my maths channel🙏🙏 Here I do upload


Welcoem to posts!!

in the future - u will be able to do some more stuff here,,,!! like pat catgirl- i mean um yeah... for now u can only see others's posts :c

Me Asthmatic_M@thematics.
Posted 3 weeks ago

May be I don't have enough time for Post and manage my channel but I always try my best to reach out to you guys and add some valuable content for you. This channel community has been opened for all of you guys to share, discuss your opinion on the topic related to Maths. Now onwards you can post your problem, opinion and discussions you wanna make with us or me, I will try my best to responds your post.
In the end hearty welcome to you guys to my *Channel Community*. Make sure you guys will post and feel free to use this well.

Thank you.
‪@measthmatic_mathematics.‬

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Me Asthmatic_M@thematics.
Posted 4 months ago

Why -> How -> what ❓

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Me Asthmatic_M@thematics.
Posted 6 months ago

Isn't it amazing 🤔 In Mathematics we study imaginary number for real application which itself exist in imaginary but they really exist😄 (Imagine a imaginary plane for imaginary number.) : ) Mathematics can go far beyond our imagination : )
Love maths ❤️...


#funthings #maths #enjoymaths #lovemaths

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Me Asthmatic_M@thematics.
Posted 9 months ago

Happy National Mathematics Day ❤️

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Me Asthmatic_M@thematics.
Posted 10 months ago

Which is more difficult??

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Me Asthmatic_M@thematics.
Posted 11 months ago

190700131099241420990620241899051417
4000
1820011802170801041718
Decrypt this message 😁...👋

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Me Asthmatic_M@thematics.
Posted 1 year ago

Dear Enthusiast, I bring for you an interesting method of finding divisors of any numbers.
Say , for n= 99 ,this can be written as n=3×3×11 by Fundamental Theorem of Arithmetic.
Now, let's say the number of divisors are expressed by d(n), then d(n)= d(p1×p2×......×pk)
= (1+1)×(1+1)×(1+1).....(1+1) (k times)
This is only for the case if exponent = 1. If exponent>1 then, d(n) = d(p1^k + p2^s+....) =( k+1)×(s+1)...
Here in my example,d(99)= d(3^2 ×11) = (2+1)× (1+1)=6.
Therefore, the number of divisors of 99 is 6 i.e 1, 3, 9, 11, 33 and 99.

If you like such type of discussion in this community then LIKE , SHARE and SUBSCRIBE . And also comment your view. 👍
Bye bye and Good night.

‪@measthmatic_mathematics.‬

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Me Asthmatic_M@thematics.
Posted 1 year ago

If a function f is partially differentiated then the function is

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