Smart Learning with Saloni

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04:35

If sinθ+cosθ=√3, then prove that tanθ+cotθ=1

05:37

In ΔPQR, right-angled at Q. PR+QR=25 cm and PQ=5 cm. Determine the values of sin P, cos P, tan P

03:07

Prove that: (cosecθ−cotθ)2=1−cosθ/1+cosθ | Trigonometry | Class10th | ImportantQuestion |

04:43

Prove that : √(1+cosθ/1−cosθ)+√(1−cosθ/1+cosθ)=2cosecθ | Trigonometry | Class10th | Chapter 8 |

06:35

Prove that:(cot^3 θ.sin^3θ)/(cosθ + sinθ)^2 + (tan^3 θ.cos^2θ)/(cosθ + sinθ)^2=(secθcosecθ-1)/(cosec

03:49

Prove that: tan² θ / (sec θ - 1)² = (1 + cos θ) / (1 - cos θ) | Trigonometry | Class10th | Maths |

07:08

Prove that tanθ/1−cotθ+cotθ/1−tanθ=1+secθcscθ | Trigonometry | Class10th | ImportantQuestion |

03:57

Prove that √1−cosθ/1+cosθ =cosecθ−cotθ. Trigonometry | Class10th |

03:57

Prove that: √1 + sin θ/1 - sin θ=sec θ+tan θ | Class10th | Trigonometry |

05:40

The 10th term of an AP is - 37 & sum of first 6 terms is - 27. Find the sum of first eight terms.

05:08

The 14th term of an AP is twice its 8th term. If 6th term is −8, then find sum of its first 20 terms

05:19

Find the sum of integers between 100 and 200 that are divisible by 6...........

04:15

In an AP, the sum of the first n terms is 3n^2/2 + 13n/2. What is the 25th term?

09:22

An AP consist of 37 terms.sum of the 3 middle terms is 225 & sum of last three is 429. Find the AP

08:56

Find four numbers in A.P. whose sum is 20 and the sum of whose squares is 120.

08:30

Divide 32 into four parts which are in AP such that the product of extremes to the means is 7:15

05:17

The sum of three terms of AP is 21 & product of 1st & 3rd term exceeds the second by 6, find 3 terms

05:59

The sum of three numbers in AP is 21 and their product is 231. Find the numbers.

04:43

If Sₙ denotes the sum of first n terms of an AP, prove that S₁₂ = 3(S₈ - S₄)

04:49

If 10 times the 10th term of an AP is equal 15 times the 15th term, show 25th term of the AP is zero

07:10

Divide 56 in four parts in A.P. such that ratio of the product of their extreme to their mean in 5:6

05:16

Ratio of sum of m and n terms of an A.P is m2:n2 show the ratio of mth and nth term is (2m-1):(2n-1)

06:53

If the sum of first m term of an AP be n and n terms be m.show the sum of first (m+n)terms is −(m+n)

04:53

If (m+1)th term of an A.P is twice the (n+1)th term, prove (3m+1)th term is twice the (m+n+1)th term

06:19

If sum of first m term of an AP is same as sum of n term, show that sum of its (m +n) term is zero

05:25

In an A.P., if pth term is 1/q and qth term is 1/p, prove that the sum of pq terms is 1/2(pq+1)

04:38

If the pth term of an AP is q and the qth term is p, prove that its nth term is (p+q-n) | Important|

05:14

If mth term of an AP in 1/n and nth term of it is 1/m.Show that: (mn)thth term of this AP is 1. Imp

11:32

All Formulas | Surface Area And Volume | Maths | Class 9th and 10th |

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