Views : 1,188,971
Genre: Gaming
Date of upload: Aug 27, 2022 ^^
Rating : 4.976 (343/57,088 LTDR)
RYD date created : 2024-05-11T02:33:54.964057Z
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Top Comments of this video!! :3
The answer to that problem at the end is x^2/y^4 which can also be written as (x/y^2)^2
You first do x^-7+3/16 (signs are flipped when same base exponents are moved from division to multiplication) which gives you x^-4/16 = x^-1/4
Next you multiply both the x and y exponents with -8 to give you x^2 and y^-4 which can be written as x^2/y^4
Also, I loved thymesia after elden ring, looking forward to that new lies of p game now
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the answer is x^2/y^4. First you switch the x^-3/16 back up (because negative powers switch which side of the fraction line they are on) and the x^-7/16 would go down. Some of the x's cancel, because when you divide exponents by each other, you just subtract the powers: 3/16 - 7/16 = -4/16. Since the power over the x is now negative it goes back to the denominator; however, with the -8 power waiting outside, you multiply the powers making it x^-2. Since it is a negative again, you need to switch it back up. The x's are finally done leaving x^2 on top. Now the y's are a lot easier. Y^1/2 times -8 makes it y^-4. Once again, since the exponent is negative, it goes to the bottom (the denominator). So you are left with x^2/y^4. Love your vids Zanny. Hope Solar got some help earlier (I am late to this video).
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As a fellow Sekiro lover, I'm happy to see you enjoy this game as much as I did. Such a satisfying combat system that actually holds a candle to Sekiro. You can in fact deflect any attack that isn't a critical attack with the green flash, or the ultimates with the red flash used by the bosses. So yes, you can deflect even The Hanged Queen.
My only problem is I want there to be more. Speaking of which, if you do the side quests, each zone has another unique boss fight.
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That math problem is actually pretty easy. The -8 means it is 1/expression. So when looking at the expression, since it is all multiplication and division you can multiply the exponents of each variable by 8. This will give (x^(-7/2)y^4)/x^(-3/2). Since the exponents for the x in the numerator and denominator of the expression are equal in the denominator of their exponents, they can simplified into one single x. Since it is division, the exponents will be subtracted from each other which will look like x^((-7/2) - (-3/2)) = x^((-7/2) + (3/2)) = x^(-4/2) = x^(-2) = 1/x^2. So the final expression amounts to 1/(y^4/x^2) = x^2/y^4.
Edit: I was drunk as fuck when I wrote this and accidentally typed x/2 instead of 1/x^2.
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The answer to your friend's maths problem is x^2 / y^4.
First, you simplify the two x terms. Something in the form x^n / x^m = x^(n-m), so the x terms become x^-1/4.
Then I applied the negative of the outside power, making the expression 1 / (x^-1/4 * y^1/2).
Then, you apply the outside power by multiplying the x and y's powers, as (x^n)^m = x^(nm). This gives us 1 / (x^-2 * y^4).
The last step is to move the x term to the top of the fraction. You can do this because the power is negative.
Thus, the most simplified form is x^2/y^4.
(I haven't done maths for a while so if I'm wrong please correct me)
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@theonlyzanny
1 year ago
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