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121,658 Views • Oct 11, 2022 • Click to toggle off description
Topics discussed:
1. Understanding of overflow.
2. How to recognize overflow for unsigned numbers and numbers in 2’s complement form.
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#COAByNeso #ComputerOrganizationAndArchitecture #Overflow
Views : 121,658
Genre: Education
Date of upload: Oct 11, 2022 ^^
Rating : 4.832 (76/1,738 LTDR)
RYD date created : 2024-04-29T03:23:39.22124Z
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YouTube Comments - 43 Comments
Top Comments of this video!! :3
is the s2 is coreect that show -8 ... if msb indicates sign represents then its result -0;
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Good explanation sir
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Thank you so much sir .This video so much helpful 😊
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very great video
thanks
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you are the best 🔥🔥🔥
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Great Video
❤️❤️❤️
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Thanks a lot
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Good explanation. Question! If I subtract two unsigned numbers e. g. 2 - 7 in binary 0010 - 0111
I guess that I can not caluclate the result because I have unsigned numbers. They are always positive. What happens in this case. Is there a carry? Is there a overflow? Thank you for your help in advance!
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on scenario 1 at 9:18, the two negative numbers added obtained a negative result so wouldnt there be no overflow?
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I 3rd scenario is confusing since the first scenario is giving a different point .
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In s1, -16 +6 = -10 which is same as -7-3 = -10. How did s1 became overflow? Both -7 and -3 are -ve numbers and result -10 is also -ve
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Is there like a college who produces this? Can I go there?
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that's so good brother, you are a god level teacher all over the world ,, :) thanks to you soo much broother ❤❤❤❤❤
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What is stk500 error?
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What about unsigned Substraction????
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Observe?
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thanks
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I think you have made a mistake in S1. We would consider 4 bits of the result only 0110 and this would sum up to 6. Now since we know that we added 2 negative numbers and the result we got has a positive sign (+6) so now we will say it is a case of overflow as we would need 5 bits to represent -10.
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Heeeeeeeelloooooo everyone~
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@RSA_Shock
1 year ago
thanks so much helped clear up some stuff
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