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Audio Format: 140 ( High )
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Date : 1732224610856 - unknown on Apple WebKit
Mystery text : dWh0djR0UmtxWUkgaSAgbG92ICB1IGV1LXByb3h5LnBva2V0dWJlLmZ1bg==
143 : true
1,053,973 Views • Jun 10, 2024 • Click to toggle off description
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#manim #math #mathshorts #mathvideo
#construction #geometry #mtbos #manim #animation #theorem #pww #proofwithoutwords #visualproof #proof #iteachmath #spiral #theodorus #squareroot
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Views : 1,053,973
Genre: Education
License: Standard YouTube License
Uploaded At Jun 10, 2024 ^^
warning: returnyoutubedislikes may not be accurate, this is just an estiment ehe :3
Rating : 4.937 (1,204/75,780 LTDR)
98.44% of the users lieked the video!!
1.56% of the users dislieked the video!!
User score: 97.66- Overwhelmingly Positive
RYD date created : 2024-11-21T21:06:31.951577Z
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944 Comments
Top Comments of this video!! :3
I don't think I'd be able to construct sqrt(200), except as 10sqrt(2).
4.7K |
"Spiral of Theodorus" sounds like some maguffin from a new Indiana Jones movie
2.8K |
Nice! finally something new to put on every image besides the golden ratio
1.5K |
"Do you think you could construct this by hand?"
Ammonites: "I don't even need hands"
449 |
The lore behind that first triangle is quite... "irrational"
1.9K |
Once it gets bigger it kinda looks like a fancy spiral seashell. It's really pretty.
65 |
my teacher made us draw an entire page of this thing, thanks for reminding me of this traumatic experience
568 |
I like the pacing of this short. Very contrary to the seemingly rushed speech and lack of breaks of other shorts
59 |
damn he really wanted to know if I think I could construct this by hand
632 |
There is a much simpler and non-recursive way to construct sqrt(n) using the fact that sqrt(n)=sqrt(n*1) which is the geometric mean of n,1. The geometric mean of two numbers a,b can be seen as a perpendicular to a diameter of a circle with length n+1 when the perpendicular stops when it touches the circle. In other words, you can first construct n+1, which is a pretty simple task, then bisect the segment to get the center of the circle. Then you can draw the circle, draw a perpendicular line 1 units from the end of the segment and voila your sqrt(n) is just the length of that perpendicular segment.
57 |
I heard spiral out. The TOOL fan in me has been awoken.
107 |
I remember learning this 9th class but couldn't fully understand it back then
433 |
Sounds like a cool way to compute the square roots. Actually, I wonder how computers do that in the first... New rabbit hole, here I go!
166 |
then visual representation of the spiral motivates the conjecture, that the difference of the radius between the loops remain constant. Then one could draw the spiral with a pencil limited by a thread winded up around a cylinder with radius=1 in the center which is rolling off by drawing. The difference between loops therefore is constantly 2*pi.
9 |
Even when you are not a math person, this is all the way fascinating…
4 |
Clearest explanation ever
12 |
Lol I actually found this by myself just doodling some triangles. Super cool that you can get measurements for basically any square root’s values this way!
31 |
I can't figure out the point of using the compass, since you don't show using it to find the perpendicular of your √ line. You can make this construction with just a right-angle triangle ruler for your straight edge.
43 |
I actually saw this in a Maths Masterclass I attended at the beginning of this year (hosted by Ri, rly good btw) and then I got it on the Intermediate Maths Challenge later this year and felt powerful because I knew the answer to the question
2 |
@CatOnACell
5 months ago
no, but this will be a great tool for drawing seashells in the future.
12K |