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338 Comments
Top Comments of this video!! :3
When java is less verbose than python in your example, you know you've screwed up somewhere
354 |
For those of you who are curious, he's got six "A"s in a row there. That's known as a "homopolymeric run" of nucleotides--in this case adenines. Because adenine forms an incredibly weak bond with itself, "A"s and "T"s have a limit to the length of a homopolymeric run before it creates debilitating cruciforms. That number is unknown, but there is a 30,000-long run of "A"s at the end of human mRNA critical to its functionality.
22 |
It’s more efficient to do it in one for loop without zipping because then you can return early if the mismatch is found
10 |
Good job you got the lest efficient solution on the lest efficient language and you felt like showing everyone
1 |
[idx for idx,(a,b) in enumerate(zip(seq1,seq2)) if a!=b]
Gives an ordered list of missmatch indexes. Or you can use {} or () instead of [] to get a set or a generator
Also I'm pretty sure there is a built-in/first party module function to do this
11 |
Hey thanks your shorts definitely give me bits of insight! I'm just messin around with pygame atm lol
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You can do this with one line of code but you managed to do a super complex program instead. Genius.
16 |
Print([ i for i in range(min(len(seq1),len(seq2))) if seq1[i] != seq2[i] ])
4 |
This was great also to be even more concise. You could replace the four loop with a list comprehension.
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Haskell version below that returns a collected list of indices for which the two characters don’t match.
example :: String -> String -> [Int]
example seq1 seq2 = mapMaybe (\(i, x1, x2) -> if x1 /= x2 then Just i else Nothing) $ zip3 [0..] seq1 seq2
Alternatively, returning a list of triple tuples of the index and the two non-matching characters
example :: String -> String -> [(Int, Char, Char)]
example seq1 seq2 = mapMaybe (\tup@(_, x1, x2) -> if x1 /= x2 then Just tup else Nothing) $ zip3 [0..] seq1 seq2
2 |
This is nice. But for bioinformatics you can do more coplec sequence alignments/BLASTs using biopython.
79 |
That is like 3 times less efficient than simply iterating through the sequences
EDIT:
It's not. zip and enumerate return generators, so the results of each "step" are lazily-evaluated. The performance of the two solutions would be almost the same
534 |
[i for i, (x,y) in enumerate(zip(str1, str2)) if x != y]
2 |
Imagine having 2 strings, making a 2d array out ig them, then turning it into a 3d array and then just printing the index 💀
214 |
thanks for the tip
1 |
😮 please more contents like this
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This is damn helpful ❤
1 |
For i in range(0..min(len(seq1),len(seq2))
If(seq1[i]!=seq2[i])
Print(i)
1 |
That's basically just enumerate(zip()), pretty common for loop in Python
14 |
@superleesa2629
1 year ago
for i in range(len(seq1)):
if seq1[i] != seq2[i]:
print(i)
2K |