PokeVideoPlayer v0.9-rev1 - licensed under gpl3-or-later
ImmersiveAmbientModecolor: #f9f2e7 (color 1)
Video Format : (720p) openh264 ( https://github.com/cisco/openh264) mp4a.40.2 | 44100Hz
Audio Format: 140 ( High )
PokeTubeEncryptID: 33c2ddbf2d87cde777c7f9d6491423cae2e90720a39e5b927eb30e562260d9e079b0c356e70eb53f733834fb6b877b03
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Date : 1727840577585 - unknown on Apple WebKit
Mystery text : cTVGZnVQa3BxdXMgaSAgbG92ICB1IGV1LXByb3h5LnBva2V0dWJlLmZ1bg==
143 : true
3,264 Views β’ Apr 27, 2024 β’ Click to toggle off description
Views : 3,264
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Uploaded At Apr 27, 2024 ^^
warning: returnyoutubedislikes may not be accurate, this is just an estiment ehe :3
Rating : 4.871 (4/120 LTDR)
96.77% of the users lieked the video!!
3.23% of the users dislieked the video!!
User score: 95.16- Overwhelmingly Positive
RYD date created : 2024-05-15T00:32:10.610855Z
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YouTube Comments - 4 Comments
Top Comments of this video!! :3
In first part, you are wrong. There was no copy at line number 8. The variables are pointing to memory location of two immutable string constants.
In both cases its copy by reference.
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In second example try q.another = "abc", then line number 21 would print another too, even when it was assigned to q and never copied to p.
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@samarpanharit4268
5 months ago
Actually for strings, x and y both point to same memory address. So address of string value stored in both x and y is same (interning). Technically itβs copy by reference. When a new value is set in x , y is still pointing to the original value and address of new string is stored in x
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