PokeVideoPlayer v23.9-app.js-aug2025_
0143ab93_videojs8_1563605_YT_2d24ba15 licensed under gpl3-or-later
ImmersiveAmbientModecolor: #bb9b87 (color 2)
Video Format : 136 (720p) mp4 | h264 | 44100Hz | 1095731 bps
Audio Format: 140 (AUDIO_QUALITY_MEDIUM) m4a | aac | 44100hz | STEREO(2channels)
PokeEncryptID: f3dc1e3a7f51c862b0b4d56b1f82eeb0d5f57526dd1a908534aa9105e6620234c4fee49fc2631405992e1ec03743dd81
Proxy/Companion URL : woke-proxy.
Date : 1759858813989 - unknown on Apple WebKit
Mystery text?? : bkpFeVdZNENER28gaSAgbG92ICB1IHdva2UtcHJveHkucG9rZXR1YmUuZnVu
143 : true
20,988 Views ⢠6 months ago ⢠Click to toggle off description
Discover how buoyancy and tension interact in this physics experiment! Learn why a wood sphere attached to a beaker changes the scale reading, even though itâs submerged like a steel sphere. Perfect for students exploring forces, buoyancy, and tension.
Want to learn more? See my video âBuoyant Force Demonstration with Steel and Oak Spheresâ.
www.flippingphysics.com/buoyant-force-spheres.html
#BuoyantForce #TensionForce #Submerged
Views : 20,988
Genre: Education
License: Standard YouTube License
Uploaded At 6 months ago ^^
warning: returnyoutubedislikes may not be accurate, this is just an estiment ehe :3
Rating : 4.729 (91/1,251 LTDR)
93.22% of the users lieked the video!!
6.78% of the users dislieked the video!!
User score: 89.83- Overwhelmingly Positive
RYD date created : 2025-03-24T19:25:19.446994Z
See in json
88 Comments
Top Comments of this video!! :3
Didnât understand till I rewatched and paid attention to you zeroing out the scale, makes perfect sense now.
20 | 0
Been watching your videos for my AP physics c class. Watching them actually doubled my failing grade. Still failed the previous quarter, but I failed with a higher grade. Pleas continue for people like me! đ
19 | 3
Wood is less dense than water. Easy
Only reason the metal doesnt make the scale go up is that theres a string taking some* of its weight
*happens to be that the string only needs to bare the load of the difference between the mass of the sphere and its boyant force, meaning the remaining boyant force is left imparting back on the beaker/water making the scale read as if it were just water
12 | 1
NO! The density of the wood is much less than that of the water. Thus the collective weight is less than the water alone because the average density of everything in the beaker has gone down slightly.
The steel ball doesn't shift the weight up because it is being suspended. If it was allowed to sit at the bottom the scale would read a positive value.
18 | 3
Could also think of it as wood being less dense causes overall density of the combination to be lower.
Since volume is the same, mass must be less.
5 | 2
So... does this mean the magnet pull car thing could work?
4 | 3
It seems this is a little unintuitive for the audience. A lot of people are confused here. But it checks out if you work through whatâs going on. The steel ball demo is missing a sphereâs volume worth of water and therefore a sphereâs volume worth of water weight than the first with no ball in it. So, there is less downward force. But the steel ball is displacing its volume of water creating an upward buoyant force which is also creating an equal downward force (Newtonâs Third Law). This essentially is replacing the missing weight of water for the scale.
The wooden ball is in the same situation, same missing water, same replaced force. HOWEVER, as he says thereâs the string tension to consider. There is now an upward tension force equal to that buoyant force. Making it lighter.
1 | 0
The trick is the metal ball. Because it's heavier than water, it's resisting the buoyancy force of the water. So even though it's in the same place, it's actually exerting a downward force in that system, to maintain it's position, resisting the buoyancy force.
Because the scale was zero'd with the metal ball, replacing it with the tied down wood ball is a slight of hand move to make you think it's all about the wood. It's actually all about the metal ball.
| 1
so a bit of wax stuck to the bottom of a jar when filled with water causes is to be lighter until the wax is heated and floats to the top?
cause that's what you're saying here.
| 4
Man I was only thinking volume unit you explained why
| 0
I see the data and the math checks out, it does feel wrong though! Data doesnt care much for feelings though haha.
Question - If you froze the water so the particles stop moving, would that remove the buoyant force (it would to my understanding of how buoyant force works) and return the scale reading to zero? or because Ice is less dense than water, it would lower the buoyant force by the % difference in density between water and ice?
2 | 3
what happens if you cut the string for the wooden ball? would it equalize? If so, why? It seems like some of the ball would be outside of the water at this point, and that seems relevant. Would the exposed portion of the ball be equivalent in volume to the same volume of water that would need to be displaced to represent 0.23 newtons?
| 1
You can almost think of the wooden ball as âliftingâ the beaker up slightly.
| 0
What happens with a wooden ball held under water from above with a rod of some sort?
| 3
Best physics teacherďźlove your videosďźso helpful
| 0
I'm more confused why the 500ml full breaker and the now less than 500ml breaker with the steel ball on a string is the same weight
| 3
Youâre wrong about this one. The wooden ballâs string being in tension isnât what causes the difference
1 | 3
If you push the wooden sphere down with a stiff stick from above, you get 0.
| 0
The steel sphere and strings are misleading, basically just replaced a volume of water with wood, of course it got lighter
| 0
@planetmezo1145
6 months ago
The reason we have a negative figure in the experiment has nothing to do with the string pulling up the glass, in fact the wood example shows exactly what we would expect. Displacing water with an equal area of wood should result in a lighter weight due to density differences. it is more correct to point to the inconsistency in the steel sphere's set up. The tension holding the sphere is not calculated in the weight of the beaker, the water pushing up against the steel sphere can only exert pressure equal to the weight of the water it displaces, so by suspending the sphere we isolate that force, which is transfered through the water to the beaker, and eventually read by the scale.
If we placed a tension gauge on the string above the steel ball, we would find a reading equal to the weight of the steel ball minus the weight of the water it displaces. This is why we see the weight measurement equal to that of straight water. The same is not true for the wood ball, being attached to the glass means all forces are taken into account by the scale, and thus we see the reduction in weight. The force of the water pushing against the steel ball is transfered through the water to the beaker and added to the weight on the scale, and because it happens to be equal to the weight lost by the displaced water we end up with 0 change.
42 | 7