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RYD date created : 2024-10-25T17:57:44.39492Z
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Top Comments of this video!! :3
The outside copper coil will heat up slower, but the inside copper coil will deteriorate faster (which makes it an inferior solution).
Now if you were to place a stainless steel enclosure around the inner coil so that it won't directly be subjected to exhaust products, that would be a better long term solution.
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The thermosiphon will heat the water faster because the stove with the pump only has 53 cubic ins. of water in the coil, whereas the thermosiphon has 183 cubic ins. of water in its coil. Thus, the thermosiphon is heating up more than three times the volume of water than the other stove in the same amount of time.
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The first one gets 1000c all around and 2nd one gets 450c heat transfer to the pipe . It's wrapped but water inside cools it down on the other side so 1st one gets 50% surface area at 1000C and 50% at 500C. The 2nd gets 50% surface area at 450-600C and other 50% of it at lower temp let's say 300C. The 1st one wines but will leek sooner
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Definitely the 2nd one. You should remove some of the steel pipes wall thickness on a lathe or something. Would make it lighter in weight and the coil would get heat transfer more efficiently. If you reduced the pipe thickness by 50%, it should still be strong enough and not melt. You're on to something.... keep going strong with your ideas.
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@sentinel9046
5 months ago
To eliminate variables, You should do a direct comparison with each stove setup with the same thermosiphon, same staring temp H2O, same grade of wood, etc. Same size coil etc. Then change 1 variable at a time to understand the effects of control variables.
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