PokeVideoPlayer v23.9-app.js-020924_
0143ab93_videojs8_1563605_YT_2d24ba15 licensed under gpl3-or-later
Views : 9,431
Genre: Education
License: Standard YouTube License
Uploaded At Nov 21, 2024 ^^
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Rating : 4.987 (2/617 LTDR)
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User score: 99.52- Masterpiece Video
RYD date created : 2024-11-28T14:16:02.212265Z
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@lillii9119
5 days ago
Now if you need to do it with BIG values, you can separate the sum into 3Σ(n) - Σ(1)
Since your sum has (b-a+1) terms, Σ(1) will add (b-a+1) times the number 1 and you get (1)(b-a+1) = (b-a+1)
Σ(n) can be found with the formula (b(b+1)-a(a-1))/2, which you then multiply by 3.
So Σ(3n-1) = (3b²+b+5a-3a²)/2 - 1
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