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Lean for free speed like McDavid (What is lean???)
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1,271 Views • Apr 2, 2023 • Click to toggle off description
Leaning is one of the many ways that McDavid creates a mechanical advantage over his opponents and gets free effortless speed on his crossovers? BUT, what is lean, and how does it work? ➡️ Watch this #short to find out.

Full video (Physics of "leaning") ➡️    • How to get McDavid LEVEL lean on cros...  

6 Practical tips & drills to improve your lean ➡️    • How to get McDavid LEVEL lean on cros...  
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Views : 1,271
Genre: Sports
License: Standard YouTube License
Uploaded At Apr 2, 2023 ^^


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Rating : 5 (0/52 LTDR)

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RYD date created : 2023-07-04T07:48:08.973319Z
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1 Comments

Top Comments of this video!! :3

@ly9nd

5 months ago

No offense, but I believe you are confused between various different things.

Lean does not make you go fast, rather lean is required to go fast around a curve, simply leaning won't do anything - this is why you will fall if you simply lean - skater has to actively turn to not fall when leaning or keep crossing over.

A skater will need to generate centripetal force to go in a curved path, that force does not come from the lean, it actually is generated by legs doing to crossover as skater keeps stepping inward ( and they actually will go tangentially if they stop doing crossover or if they stop actively trying to turn with the ankles ).

The reason lean is needed is so that centrifugal force won't topple over the skater.

The net torque in the frame of reference of the skater should be 0. assuming the lean to be theta with the vertical ( so 0 degree means 0 lean )

mv^2/r cos ( theta ) = mg sin ( theta )
tan ( theta ) = v^2/2rg

so the faster you go the more you need to lean otherwise you will be thrown out of the circle ( which will icrease r and reduce the theta ) or you will simply topple over.

The net force must also be balanced ( assuming 0 acceleration ), this is very complicated equation and simply saying centrifugal force = friction force would be incorrect as edges dig into the ice, and there are other force involved.

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